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How many roots does the function have? f(x)= x^6 + 2x^5 - 2x^4 + 3x^3 + 4x^2 - 5x +7
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1 vote
How many roots does the function have? f(x)= x^6 + 2x^5 - 2x^4 + 3x^3 + 4x^2 - 5x +7

User Pavot
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1 Answer

3 votes

Answer:

6

Explanation:

The order of the polynomial is 6 (look at the highest exponent). So there are 6 roots.

User Quinn Wei
by
5.6k points
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