Question

During a titration experiment, a 150.0 mL solution of 0.05 M sulfuric acid (H₂SO₄) is neutralized by 300.0 mL solution with an unknown concentration of sodium hydroxide (NaOH). What is the concentration of the sodium hydroxide solution?

Answer 1

Answer: The concentration of the sodium hydroxide solution is 0.05 M

Step-by-step explanation:

`H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O`

To calculate the concentration of the sodium hydroxide solution, we use the equation given by neutralization reaction:

`n_1M_1V_1=n_2M_2V_2`

where,

`n_1,M_1\text{ and }V_1` are the n-factor, molarity and volume of acid which is
`H_2SO_4`

`n_2,M_2\text{ and }V_2` are the n-factor, molarity and volume of base which is NaOH.

We are given:

`n_1=2\\M_1=0.05M\\V_1=150.0mL\\n_2=1\\M_2=?\\V_2=300.0mL`

Putting values in above equation, we get:

`2* 0.05* 150.0=1* M_2* 300.0\\\\M_2=0.05M`

Thus the concentration of the sodium hydroxide solution is 0.05 M