Question

The electric force between two identical positively charged ions is 33 × 10 − 9 N when they are 0.50 nm apart. How many electrons are missing from each ion?

Answer 1

There are 5.98 electrons are missing from each ions.

Step-by-step explanation:

Given that,

The electric force between two identical charges is,
`F=33* 10^(-9)\ N`

The distance between the charges,
`d=0.5\ nm=0.5* 10^(-9)\ m`

The electric force between charges is given by :

`F=(kq^2)/(d^2)`

`q=\sqrt{(Fd^2)/(k)}`

`q=\sqrt{(33* 10^(-9)* (0.5* 10^(-9))^2)/(9* 10^9)}`

`q=9.57* 10^(-19)\ C`

Let there are n number of electrons are missing from each ions. It is given by :

`n=(q)/(e)`

`n=(9.57* 10^(-19))/(1.6* 10^(-19))`

n = 5.98 electrons

So, there are 5.98 electrons are missing from each ions. Hence, this is the required solution.