Question

A 13 g rubber stopper is swung in a horizontal circle with a radius of 0.85 m with a period of 0.65 s. (a) How fast is the stopper moving? (b) What is the centripetal acceleration of the stopper? (c) Find the centripetal force that is exerted on the stopper.

Answer 1

Step-by-step explanation:

(a) v = 2π r / t

v = 2π (0.85 m) / (0.65 s)

v = 8.2 m/s

(b) a = v² / r

a = (8.2 m/s)² / (0.85 m)

a = 79 m/s²

(c) F = ma

F = (0.013 kg) (79 m/s²)

F = 1.0 N