Question

The velocity of a particle along the s-axis is given by v=5s^(3/2), where s is in mm and v is in mm/s. If the particle starts from rest, determine the acceleration when s is 2 mm. Express answer in mm/s^2

Answer 1

Answer: 150mm/s^2

Step-by-step explanation:

S=2mm

V=5S^(3/2)

Acceleration (a) =dv/dt

a=5*3/2*S^1/2(ds/dt)

a=15/2*S^1/2(V)

a=7.5*S^1/2(5S^3/2)

a=(7.5)*(5)*(S^2)

a=(7.5)*(5)*(4)=150mm/s^2.