Question

A nitrogen laser pulse with a wavelength of 337 nm contains 3.83 mJ of energy. How many photons does it contain?

Answer 1

number of photon will be equal to
`5.827* 10^(15)photon`

Step-by-step explanation:

We have given wavelength of nitrogen laser pulse is 337 nm

So wavelength
`\lambda =337nm=337* 10^(-9)m`

Velocity of light
`c=3* 10^8m/sec`

Plank's constant
`h=6.6* 10^(-34)Js`

So energy of each photon
`E=(hc)/(\lambda )=(6.6* 10^(-34)* 3* 10^8)/(337* 10^(-9))=5.8* 10^(-19)J`

Total energy is given = 3.38 mJ = 0.00338 J

So number of photon will be equal to
`=(0.00338)/(5.8* 10^(-19))=5.827* 10^(15)photon`

So number of photon will be equal to
`5.827* 10^(15)photon`