Question

How much work would it take to push two protons very slowly from a separation of 2.00×10−10m (a typical atomic distance) to 3.00×10−15m (a typical nuclear distance)?

Answer 1

Work= -7.68×10⁻¹⁴J

Step-by-step explanation:

Given data

q₁=q₂=1.6×10⁻¹⁹C

r₁=2.00×10⁻¹⁰m

r₂=3.00×10⁻¹⁵m

To find

Work

Solution

The work done on the charge is equal to difference in potential energy

W=ΔU

`Work=U_(1)-U_(2)\\ Work=-kq_(1)q_(2)[(1)/(r_(2))-(1)/(r_(1)) ]\\Work=(-9*10^(9))*(1.6*10^(-19) )^(2)[(1)/(3.0*10^(-15) )-(1)/(2*10^(-10) ) ]\\ Work=-7.68*10^(-14)J`