179k views
4 votes
Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perimeter. Give your answer as a completely simplified exact value in terms of π (no approximations).

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles-example-1
User Infinity
by
4.6k points

2 Answers

3 votes

Answer:

36(π-2)cm^2 is area

Perimeter is 6(π+2√2)

Explanation:

User Ulrike
by
4.4k points
5 votes

Answer:

Part 1)
A=36(\pi-2)\ cm^2

Part 2)
P=6(\pi+2√(2))\ cm

Explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so


A=(1)/(4)\pi r^(2)-(1)/(2)(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle


r=12\ cm\\b=12\ cm\\h=12\ cm

substitute


A=(1)/(4)\pi (12)^(2)-(1)/(2)(12)(12)


A=(36\pi-72)\ cm^2

simplify

Factor 36


A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to


C=(1)/(4)(2\pi r)=(1)/(2)\pi r

substitute the given values


C=(1)/(2)\pi (12)


C=6\pi\ cm

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)


AC=√(12^2+12^2)


AC=√(288)\ cm

simplify


AC=12√(2)\ cm

Find the perimeter


P=(6\pi+12√(2))\ cm

simplify

Factor 6


P=6(\pi+2√(2))\ cm

User Iftheshoefritz
by
4.2k points