Question

Create the equation of a line that is perpendicular to 2y=14+(2/3) x and passes through the point (-2,8).

Answer 1

y = -3x +2

Explanation:

If you divide the equation for the given line by 2, it will be in slope-intercept form:

y = (1/3)x +7

This tells you its slope is 1/3. The slope of the perpendicular line is the negative reciprocal of this: -1/(1/3) = -3. The point-slope form of the equation for the perpendicular line can be written as ...

y = m(x -h) +k . . . . . line with slope m through point (h, k)

Your line is ...

y = -3(x -(-2)) +8

y = -3x +2