Answer:
f=qB/2
m
Step-by-step explanation:
The cyclotron frequency is the number of revolutions the particle makes in one second. calculate the cyclotron frequency for this particle
solution
The Lorentz force
is the centripetal force
and makes the particles path to revolve in a circle:
qvB=mv^2/r
radius=r
m=mas of the particle
B=magnetic flux
q=quantity of charge
v=velocity of the particle
v=qBr/m
where v is the velocity of the particle
recall the velocity v=rω
v=2*Pi*f*r
=qBr/m
f=qB/2
m
the cyclotron frequency is therefore f=qB/2
m
the period(the time it take to make a complete oscillation) will be the inverse of frequency
T=2
m/qB