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Give PQ=24,PS=19,PR=42,TQ=10 mPQR=106,mQRS=49 and PRS=35

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Answer:

QR = 19

SR = 24

PT = 21

SQ = 20

m∠QRS = 74°

m∠PQS = 49°

m∠RPS = 39°

m∠PSQ = 57°

Explanation:

Attached is the complete question:

By definition, a parallelogram is a quadrilateral, which means it has 4 sides where the opposite pairs are parallel to each other. These pair of sides are congruent.

With that we can assume the following:

PQ ≅ SR

PS ≅ QR

m∠PQR ≅ m∠ PSR

m∠QRS ≅ m∠ QPS

The given states that:

PQ ≅ SR

PS ≅ QR

then:

PQ = 24

PS = 19

So we know that:

QR = 19

SR = 24

When it comes to the angles, we have the following theorems:

Opposite angles (Opposite edges) are congruent

Consecutive angles are supplementary, or they sum up to 180°

We are given the following angles:

m∠PQR = 106°

m∠QSR = 49°

m∠PRS = 35°

Based on the theorems we know the following:

m∠PQR ≅ m∠PSR

m∠PQR + m∠QRS = 180°

Then:

m∠PQR + m∠QRS = 180°

106° + m∠QRS = 180°

m∠QRS = 180° - 106°

m∠QRS = 74°

In addition, m∠PSR = 106° and m∠QSR = 49° then when we add it to m∠PSQ it should be equal to m∠PSR

m∠QSR + m∠PSQ = m∠PSR

49° + m∠PSQ = 106°

m∠PSQ = 106° - 49°

m∠PSQ = 57°

Now notice that a parallelogram when you cut them in half, it makes two congruent triangles. All angles in a triangle sum up to 180° so we can assume that:

m∠PSR + m∠PRS + m∠RPS = 180°

So:

106° + 35° + m∠RPS = 180°

141° + m∠RPS = 180°

m∠RPS = 180° - 141°

m∠RPS = 39°

Following the same logic:

m∠QPS ≅ m∠QRS

m∠QPS = 74°

m∠QPS + m∠PSQ + m∠PQS = 180°

74° + 57° + m∠PQS = 180°

131° + m∠PQS = 180°

m∠PQS = 180° - 131°

m∠PQS = 49°

Give PQ=24,PS=19,PR=42,TQ=10 mPQR=106,mQRS=49 and PRS=35-example-1
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