Answer: 0.332 < p < 0.490
Explanation:
We know that the confidence interval for population proportion is given by :-

, where n= sample size
= sample proportion
z* = critical z-value.
As per given , we have
n= 258
Sample proportion of college students who own a car =

Critical z-value for 99% confidence interval is 2.576. (By z-table)
Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be :

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490