Answer:
The speed of plane is
, and speed wind is
.
Explanation:
Given against the wind the airline flew
miles in
hours.
including the tailwind the return trip took
hours.
Let speed of plane is
.
Also, speed of the wind is
.
Now, we will find speed on each case.
Speed against the wind is
![(630)/(3.5)=180\ mph](https://img.qammunity.org/2021/formulas/mathematics/middle-school/chyd5z5r2lqzd4w0o0tzah91rvccxfyb5x.png)
Speed with the wind is
![(630)/(3)=210\ mph](https://img.qammunity.org/2021/formulas/mathematics/middle-school/99h32e1rya063kus5lietzamijnzsi76s9.png)
Now, we will write the equation
![x+y=210\\x-y=180](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1mt4v8j9gewb3c5h2oy8f1wnqlklj1aodg.png)
Add these equation we get,
![2x=390\\x=(390)/(2)\\x=195\ mph](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zjgcwtex5539vs11epln4bxx4c3tn5pn9i.png)
Now, plug this value in
to get speed of wind
![195+y=210\\y=210-195\\y=15\ mph](https://img.qammunity.org/2021/formulas/mathematics/middle-school/j5xnekir6w6lrw8zvbivxgps4wl05nsaiz.png)
So, the speed of plane in still air is
, and speed of the wind is
.