Question

Write a program that uses an array of integers initialized to whatever values you wish. Write a methods to calculate and return the minimum and a method to calculate and return the maximum values in the array. Write an additional method that accepts the array as a parameter and then creates and returns a new array with all the same values as the original plus 10.

I think I have the max and min part down, but I need help figuring how to return the new array with all the same values as the orginal plus 10....

Here is what I have so far for the max / min. please use this in helping to create a matching method that accepts the array as a parameter. :

/*

*/
package arrayvalues;

/**
*
* @author dreadsguy
*/
public class ArrayValues {

/**
* @param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
int [] numbers = {99,56,103,9,31,63,81,92,13};

int m = maximum (numbers);
int n = minimum (numbers);


System.out.println("max ="+ m);
System.out.println("min ="+ n);


}


public static int maximum (int [] numbers){
//index
int i=0;
//current maximum
int max;
//initial maximum
max = numbers[i];
//calculate maximum

for (i = 1; i < numbers.length; i++){
if (numbers[i]> max)
{
max = numbers[i];
}

}
return(max);
}

public static int minimum (int [] numbers){
//index
int i=0;
//current minimum
int min;
//initial minimum
min = numbers[i];
//calculate minimum

for (i = 1; i < numbers.length; i++){
if (numbers[i]< min)
{
min = numbers[i];
}


}
return(min);
}
}

Answer 1

Here is the additional method you need to write:

public static int [] newArrayNumbers (int [] numbers){

int [] newArray = new int[10];

for (int i=0; i<numbers.length; i++){

newArray[i]=numbers[i];

}

newArray[9]=10;

return newArray;

}

The complete code is given in the explanation section

Step-by-step explanation:

import java.util.Arrays;

public class NewQues{

public static void main(String[] args) {

int [] numbers = {99,56,103,9,31,63,81,92,13};

int m = maximum (numbers);

int n = minimum (numbers);

System.out.println("max ="+ m);

System.out.println("min ="+ n);

System.out.println(Arrays.toString(newArrayNumbers(numbers)));

}

public static int maximum (int [] numbers){

int i=0;

int max;

max = numbers[i];

for (i = 1; i < numbers.length; i++){

if (numbers[i]> max)

{

max = numbers[i];

}

}

return(max);

}

public static int minimum (int [] numbers){

int i=0;

int min;

min = numbers[i];

for (i = 1; i < numbers.length; i++){

if (numbers[i]< min)

{

min = numbers[i];

}

}

return(min);

}

public static int [] newArrayNumbers (int [] numbers){

int [] newArray = new int[10];

for (int i=0; i<numbers.length; i++){

newArray[i]=numbers[i];

}

newArray[9]=10;

return newArray;

}

}

This for statement here does the work for you. assigning the values in the first array to the second array.

for (int i=0; i<numbers.length; i++){

newArray[i]=numbers[i];

}

The second logic is, since you knew the first array had 9 elements, you create the second to have 10 elements so you can assign the element at the last index (9) the value of ten as required by the question