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How many moles of HCl are in 57 mL of 0.17 M HCl ?

User Ogee
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\text{Given that,}\\ \\\text{Volume,}~V= 57 mL = 0.057 L\\\\\text{Molar concentration,}~ S = 0.17 ~mol/L\\\\\text{Number of moles,} ~ n=?\\\\S = (n)/(V) \\\\\implies n = SV = 0.17* 0.057 =0.00969 ~mol ~ HCl

User Tom Christie
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