Question

A spring with a force constant of 5.0 N/m has a relaxed length of 2.63 m. When a mass is attached to the end of the spring and allowed to come to rest, the vertical length of the spring is 3.93 m. Calculate the elastic potential ene

Answer 1

4.225 J

Step-by-step explanation:

Elastic Potential Energy: This is the potential energy stored in an elastic material.This also the energy required to stretch an elastic material. The S.I unit is Joules.

Mathematically it is expressed as

E = 1/2ke²....................... Equation 1

Where E =elastic potential Energy, k = spring constant, e = extension.

Given: k = 5.0 N/m, e = 3.93-2.63 = 1.3 m.

Substitute into equation 1

E = 1/2(5)(1.3)²

E = 8.45/2

E = 4.225 J.

Thus the Elastic potential Energy = 4.225 J.