Question

An aqueous KNO3 solution is made using 76.6 g of KNO3 diluted to a total solution volume of 1.84 L. (Assume a density of 1.05 g/mL for the solution.) You may want to reference (Pages 552 - 557) Section 13.5 while completing this problem. Part A Calculate the molarity of the solution.

Answer 1

The answer to your question is Molarity = 0.41

Step-by-step explanation:

Data

mass of KNO₃ = 76.6 g

volume = 1.84 l

density = 1.05 g/ml

Process

1.- Calculate the molecular mass of KNO₃

molecular mass = 39 + 14 + (16 x 3) = 101 g

2.- Calculate the number of moles

101 g of KNO₃ --------------- 1 mol

76.6 g of KNO₃ ------------ x

x = (76.6 x 1) / 101

x = 0.76 moles

3.- Calculate molarity

Molarity =
`(number of moles)/(volume)`

Substitution

Molarity =
`(0.76)/(1.84)`

Result

Molarity = 0.41