Answer: Our required probability is 0.3387.
Explanation:
Since we have given that
Number of red cards = 4
Number of black cards = 5
Number of cards drawn = 5
We need to find the probability of getting exactly three black cards.
Probability of getting a black card =
![(5)/(9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nkfatn6kyo76z0n7g7vmp3nb9i405c5gng.png)
Probability of getting a red card =
![(4)/(9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pcqdctyi1yuttg94nri04x3l3sebq3p0kr.png)
So, using "Binomial distribution", let X be the number of black cards:
![P(X=3)=^5C_3((5)/(9))^3((4)/(9))^2\\\\P(X=3)=0.3387](https://img.qammunity.org/2021/formulas/mathematics/high-school/tng3ssppjq22kton5nnovanxtcxikfdozz.png)
Hence, our required probability is 0.3387.