Answer:
![1.475* 10^(-13)\ C/m^3](https://img.qammunity.org/2021/formulas/physics/college/gt1auq707nzke9ymr3ydvnd3wb5rc2w67b.png)
Step-by-step explanation:
= Permittivity of free space =
![8.85* 10^(-12)\ F/m](https://img.qammunity.org/2021/formulas/physics/high-school/k3aks2fgmlwuw4q7k2sezrqiuczavgvrq1.png)
A = Area
h = Altitude = 600 m
Electric flux through the top would be
(negative as the electric field is going into the volume)
At the bottom
![120A](https://img.qammunity.org/2021/formulas/physics/college/min0rs3lub3p9cn1n711ii2k4g6jkf303m.png)
Total flux through the volume
![\phi=120-110\\\Rightarrow \phi=10A](https://img.qammunity.org/2021/formulas/physics/college/hsf4fnxd1voj1a9j5ecy7getcglkb6x018.png)
Electric flux is given by
![\phi=(q)/(\epsilon_0)\\\Rightarrow q=\phi\epsilon_0\\\Rightarrow q=10A\epsilon_0](https://img.qammunity.org/2021/formulas/physics/college/sb7fsqygbce5zwdumd9m2fn59rzdlkcv6i.png)
Charge per volume is given by
![\rho=(q)/(v)\\\Rightarrow \rho=(10A\epsilon_0)/(Ah)\\\Rightarrow \rho=dfrac{10\epsilon_0}{h}\\\Rightarrow \rho=(10* 8.85* 10^(-12))/(600)\\\Rightarrow \rho=1.475* 10^(-13)\ C/m^3](https://img.qammunity.org/2021/formulas/physics/college/y08w6hnz5mtlzgwgvfwt512k4uyna2th2x.png)
The volume charge density is
![1.475* 10^(-13)\ C/m^3](https://img.qammunity.org/2021/formulas/physics/college/gt1auq707nzke9ymr3ydvnd3wb5rc2w67b.png)