Answer
Organ Pipe A has both end open.
Organ Pipe B has one end open.
speed of sound, v = 343 m/s
The fundamental frequency = 270 Hz
wavelength of the pipe when both end open
λ = 2 L
we know,
![\lambda = (v)/(f)](https://img.qammunity.org/2021/formulas/physics/college/s1ci2t18x0sdp9no2icy81sa9g1nmow289.png)
now,
![L = (v)/(2f)](https://img.qammunity.org/2021/formulas/physics/college/bf5hiogfqpvr80ovk9y3qanw52yfpl495m.png)
inserting all the values
![L = (343)/(2* 270)](https://img.qammunity.org/2021/formulas/physics/college/iwbk00jslrn6g9k7ha578g66w39feskcjq.png)
L_A = 0.635 m
length of pipe A is equal to 0.635 m
b) since third harmonic of pipe B is equal to second harmonic of pipe A
![f_B = f_A](https://img.qammunity.org/2021/formulas/physics/college/r94wltoo6mcuprjr9whhrjg4c5o71ruzmp.png)
![(n_BV)/(4L_B) = (n_AV)/(2L_A)](https://img.qammunity.org/2021/formulas/physics/college/wfcevqpzziutavr20boanypb89dymvxmuz.png)
![L_B= (2* 3 * 0.635)/(4* 2)](https://img.qammunity.org/2021/formulas/physics/college/j24lxumd1o54m3ruoawpr7iblurloqawbj.png)
L_B = 0.476 m
length of pipe B is equal to 0.476 m.