Question

Mark made a business trip of 214 miles. He averaged 53mph for the first part of the trip and 54mph for the second part. If the trip took 4 hours, how long did he travel at each rate?

Answer 1

He travel for 2 h at the first part and 2 h for the second part.

Step-by-step explanation:

given information:

business trip's distance,
`s_(tot)` = 214 miles

v₁ = 53 mph

v₂ = 54 mph

t₁ = t

t₂ = 4 - t

now lets find the distance of each speed

s₁ = v₁ t₁ = 53 t₁

s₂ = v₂ t₂ = 54 t₂

`s_(tot)` = s₁ + s₂

214 = 53 t₁ + 54 t₂

214 = 53t + 54 (4-t)

214 = 53t + 216 - 54 t

t = 216 - 214

= 2 h

t₁ = t = 2 h

t₂ = 4 - t = 4 -2 = 2h