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As part of a safety investigation, two 1900 kg cars traveling at 20 m/s are crashed into different barriers. Part A Find the average force exerted on the car that hits a line of water barrels and takes 1.3 s to stop.

User Meow
by
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1 Answer

4 votes

Answer:

-
29.2* 10^(3) N

Step-by-step explanation:

We are given that

Mass of cars= m=1900 kg

Initial speed of car=u=20 m/s

Final speed of car=v=0

Time=
\Delta t=1.3 s

We have to find the average force exerted on the car.

Average force=
(change\;in\;momentum)/(\Delta t)


F_(avg)=(mv-mu)/(1.3)


F_(avg)=(1900(0)-1900(20))/(1.3)


F_(avg)=(-38000)/(1.3)=-29.2* 10^(3) N

Hence, the average force exerted on the car that hits a line of water barrels=-
29.2* 10^(3) N

User Fredou
by
5.8k points