Question

What is the kinetic energy of the ball just before it hits the ground?

Answer 1

`0.5mv^(2)`

Step-by-step explanation:

Kinetic energy,
`KE= 0.5mv^(2)`

while potential energy, PE= mgh where m is the mass, v is the velocity of the ball, g is acceleration due to gravity and h is the height.

The question requires kinetic energy hence we use the
`KE= 0.5mv^(2)`

Since the figures are not given, we maintain that
`KE= 0.5mv^(2)`