Question

CFC-11 (trichlorofluoromethane, CCl3F) has been used for many years as the working fluid in refrigerators. Given its heat of vaporization is 26.88 kJ/mol and its entropy of vaporization is 90.51 J/(mol ⋅ K), what is the boiling point of CFC-11?

Answer 1

297.0 K

Step-by-step explanation:

Given data

• Enthalpy of vaporization (ΔHvap): 26.88 kJ/mol = 26.88 × 10³ J/mol

• Entropy of vaporization (ΔSvap): 90.51 J/(mol ⋅ K)

• Boiling point (Tb): ?

We can find the boiling point of CFC-11 using the following expression.

ΔSvap = ΔHvap/Tb

Tb = ΔHvap/ΔSvap

Tb = (26.88 × 10³ J/mol)/(90.51 J/(mol ⋅ K))

Tb = 297.0 K