Answer:
![x^(2) = 20y](https://img.qammunity.org/2021/formulas/mathematics/college/gpmysb2adld634owyg0rpz5hmii9093b2o.png)
Explanation:
The directrix given is vertical , so we will use the formula :
![(x-h)^(2)=4p(y-k)](https://img.qammunity.org/2021/formulas/mathematics/college/xjadniwpk7gjjjehpvcipk9trzomip9mcv.png)
P is the distance between the focus , that is 5 - 0 = 5
Therefore : p = 5
(h,k) is the mid point between the focus and the directrix , that is
(h,k) =
=
=
![(0,0)](https://img.qammunity.org/2021/formulas/mathematics/high-school/1e0myolqax3l5zzpgjq5jo70vmvfipqeak.png)
Therefore:
h =0
k = 0
substituting into the formula : we have
![(x-h)^(2)=4p(y-k)](https://img.qammunity.org/2021/formulas/mathematics/college/xjadniwpk7gjjjehpvcipk9trzomip9mcv.png)
= 4(5)(
![y-0)](https://img.qammunity.org/2021/formulas/mathematics/college/icnmxiinx90hy5tr0x97g7oycmbl0bjevp.png)
![x^(2) = 20y](https://img.qammunity.org/2021/formulas/mathematics/college/gpmysb2adld634owyg0rpz5hmii9093b2o.png)
Therefore : the equation in vertex form is
![x^(2) = 20y](https://img.qammunity.org/2021/formulas/mathematics/college/gpmysb2adld634owyg0rpz5hmii9093b2o.png)