Question

The Law of Independent Assortment describes why there is so much

diversity among offspring of a species. A female rabbit that is
heterozygous for long ears and long fur mates with a male rabbit that is
also heterozygous for long ears and long fur. What is the phenotypic ratio
of the offspring of this genetic cross?
LIFF X LIFE
8:8
8:6:2
1:1:1:1
09:3:3:1

Answer 1

9 : 3 : 3 : 1

Step-by-step explanation:

Answer 2

9:3:3:1 is the ratio.

Option D.

Step-by-step explanation:

The cross described here is actually similar to Mendel’s Dihybrid Cross where two characters of the organisms are actually taken into account and then the phenotypic ratio of the F2 offsprings are seen.

The genes for the long ears and long fur are both heterozygous in both parents. So both of the parents have a dominant allele and a recessive allele.

Lets suppose the dominant allele for the gene determining ear is E and recessive is e. And the dominant allele for the gene determining fur is F and recessive is f.

So the genotype of both the parents is EeFf.

So the gametes produced by both the parents are EF, Ef, eF and ef respectively.

Thus, if we put these in punnett square and see the offsprings, we will see that phenotypic ratio of Ling eared long furred to long eared short furred to short eared long furred to short eared short furred is 9:3:3:1.