Answer:
D.141 g
Step-by-step explanation:
Given that:-
Mass of ethylene = 45.0 g
Molar mass of ethylene = 28.05 g/mol
The formula for the calculation of moles is shown below:
Thus,

According to the reaction below:-

1 mole of ethylene produces 2 moles of carbon dioxide
So,
1.60 mole of ethylene produces 2*1.60 moles of carbon dioxide
Moles of carbon dioxide = 3.2 mol
Molar mass of carbon dioxide = 44.01 g/mol
Mass = Moles*Molar mass = 3.2 mol x 44.01 g/mol = 141 g
D.141 g of carbon dioxide will be produced