Answer:
69.74 N
Step-by-step explanation:
We are given that
Weight of sled=49 N
Coefficient of kinetic friction
![,\mu_k=0.11](https://img.qammunity.org/2021/formulas/physics/high-school/dihmzgrtcfrloudo62ytjms8ewpzpuj8l8.png)
Weight of person=585 N
Total weight==mg=49+585=634 N
We know that
Force needed to pull the sled across the snow at constant speed,F=Kinetic friction
![F=\mu_k N](https://img.qammunity.org/2021/formulas/physics/high-school/d3ic9e8c6h4f5u8berkosenaarer66z6sh.png)
Where N= Normal=mg
![F=0.11* 634=69.74 N](https://img.qammunity.org/2021/formulas/physics/high-school/7au468tfnnzqkszgz91sv0edk96vhmvwvy.png)
Hence, the force is needed to pull the sled across the snow at constant speed=69.74 N