Question

If the magnitude of a charge is twice as much as another charge, but the force experienced is the same, then the electric field strength of this charge is _____ the strength of the other charge.

Answer 1

The new electric field strength of this charge is half of the strength of the other charge.

Step-by-step explanation:

The electric force acting on the charge particle is given by :

F = q E

`E=(F)/(q)`

Where

q is the charged particle

E is the electric field

If the magnitude of a charge is twice as much as another charge, q' = 2q, but the force experienced is the same, then the new electric field is given by :

`E'=(F)/(q')`

`E'=(F)/((2q))`

`E'=(1)/(2)* (F)/(q)`

`E'=(E)/(2)`

So, the new electric field strength of this charge is half of the strength of the other charge. Hence, this is the required solution.