Answer:
The number of adult ticket sold is
![12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/71jnwngklumevr3bpoxl7oqa306a955xoz.png)
The number of child ticket sold is
![38](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l4fdoy2meg1yue1uvmvf60i957ushnvw2k.png)
Explanation:
Given cost of adult tickets are $
, and cost of child tickets are $
![4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xzed5nzvf3bf3qzg8253xj74ovp9egmyez.png)
Let the number of adult ticket sold is
![x](https://img.qammunity.org/2021/formulas/mathematics/middle-school/p9sq9b3rc5nwoqzhzc8wcaj51b36281l9g.png)
Also, the number of child ticket sold is
![y](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kkh2dol4tzoh3mam41rvldrs3zvp7rkbgp.png)
We can write two equation from given information.
![x+y=50\ Equation\ (1)\\8x+4y=248\ Equation(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8mwmguggtdiaj1bfdlp1pc3pr8y8mfakzn.png)
Now, plug
in
we get,
![8(50-y)+4y=248\\400-8y+4y=248\\-4y+400=248\\-4y=248-400\\-4y=-152\\y=(-152)/(-4)\\y=38](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8kk9iwrsegzpcurx4g67kwnxqoaz2ehozn.png)
Now, from
![Equation(1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/v7c7ah6510xcwaka8j9hes90th5v4c8w0o.png)
![x+y=50\\x+38=50\\x=50-38\\x=12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3a2oauctr37it2jbaczq9epuxsqrzz0nlg.png)
So, The number of adult ticket sold is
. And the number of child ticket sold is
![38](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l4fdoy2meg1yue1uvmvf60i957ushnvw2k.png)