Question

calculate the change in internal energy for a system taht is giving off 25.000 kL of heat and is changing from 18.00 L to 15.00 L?

Answer 1

This is an incomplete question. The complete question is :

Calculate the change in internal energy (ΔE) for a system that is giving off 25.000 kJ of heat and is changing from 18.00 L to 15.00 L in volume at 1.50 atm pressure.

Answer: The change in internal energy for a system is -24544 Joules

Step-by-step explanation:

According to first law of thermodynamics:

`\Delta E=q+w`

`\Delta E`=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=
`-P\Delta V` {Work done on the system as the final volume is lesser than initial volume and is positive}

w =
`-1.50atm* (15.00-18.00)L=4.50Latm=456Joules` {1Latm=101.3J}

q = -25.000 kJ =
`-25.000* 10^3J` {Heat released by the system is negative}

`\Delta E=456J+(-25000)=-24544J`

Thus change in internal energy for a system is -24544 Joules