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Question 10-5 (a). Consider a steady flow Carnot cycle with water as the working fluid. The maximum and minimum temperatures in the cycle are 350 and 50 C. The quality of water is 0.891 at the beginning
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Question 10-5 (a). Consider a steady flow Carnot cycle with water as the working fluid. The maximum and minimum temperatures in the cycle are 350 and 50 C. The quality of water is 0.891 at the beginning of the heat rejection process and 0.1 at the end. Determine:(a) the thermal efficiency (how much percent).

User Wismin
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4 votes

Answer:

48.2 %

Step-by-step explanation:

Given:

TL = 50 + 273 = 323 K

TH = 350 + 273 = 623 K

Thermal efficiency (Etath) of carnot cycle is:

Etath = 1 - (TL / TH )

Etath = 1 - (323) / (623) = 48.2 %

Answer: 48.2 %

User Gwelter
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