To solve this problem we will apply the linear motion kinematic equations. In which the speed is defined as the distance traveled in a certain period of time. In turn we must emphasize that 1 light year is equivalent to
. Mathematically the speed is described as,
![v = (x)/(t) \rightarrow t = (x)/(v)](https://img.qammunity.org/2021/formulas/physics/college/hebtk36q51oaab1bfocv8uryksd8kadgkn.png)
Replacing,
![t = (9.461*10^(15))/(30)](https://img.qammunity.org/2021/formulas/physics/college/6n1crrhplzqyfyf6lgycm6ohumvfupjbaj.png)
![t = 3.15366*10^(14)s ((1 year)/(3.154*10^7))](https://img.qammunity.org/2021/formulas/physics/college/9d03wv9pvv1u741pmpumg8gnzlkjidmjhc.png)
![t \approx 10,000,000 years](https://img.qammunity.org/2021/formulas/physics/college/us8v805dswmdmlylpqjtfutaycobihtuyt.png)
Therefore the correct answer is D.