Answer:
10.1 g of Al are formed
Step-by-step explanation:
The reaction is:
2AlCl3 --> 2Al + 3Cl2
So 2 moles of aluminun chloride decompose into 2 moles of Al and 3 moles of chlorine.
Ratio is 2:2.
Let's convert the mass of salt into moles (mass / molar mass)
50 g / 133.34 g/mol = 0.374 moles.
As the ratio is 2: 2, if I have 0.374 moles of salt, I would produce the same amount of Al, just 0.374.
Let's convert the moles to mass
(Mol . molar mass)
0.374 mol . 26.98 g / mol = 10.1 g of Al are formed
Ξ