231k views
5 votes
An article reported the following data on oxygen consumption (mL/kg/min) for a sample of ten firefighters performing a fire-suppression simulation: 29.6 49.3 30.1 28.3 28.7 26.3 33.5 29.8 23.7 31.0 Compute the following. (Round your answers to four decimal places.)

(a) the sample range(b) the sample variance s2 from the definition(c) the sample standard deviation(d) s2 using the shortcut method

1 Answer

5 votes

Answer:

a) Range = 25.6

b) Variance = 48.1446

c) s = 6.9386

d) See below

Explanation:

(a) the sample range

To obtain the sample range, we must sort the data increasingly :

23.7, 26.3, 28.3, 28.7, 29.6, 29.8, 30.1, 31, 33.5, 49.3

Then, find the distance between the largest and the lowest

Range = 49.3 - 23.7 = 25.6

(b) the sample variance
s^2 from the definition

In order to find the variance from the definition, we need first the mean. The mean is defined as the average


\bar x=\displaystyle(\displaystyle\sum_(i=1)^(n)x_i)/(n)

where the
x_i are the values of the data collected and n=10 the size of the sample.

So, the mean is


\bar x=31.03

Now, the variance of the sample is defined as


s^2=\displaystyle(\displaystyle\sum_(i=1)^n(x_i-\bar x)^2)/(n-1)

and we have that the variance is


s^2=48.1446

(c) the sample standard deviation

The sample standard deviation is nothing but the square root of the variance


s=√(48.1446)=6.9386

d)
s^2 using the shortcut method

The shortcut method figures out the variance without having to compute the mean. The formula is


s^2=(n\sum x_i^2-(\sum x_i)^2)/(n(n-1))

where n=10 is the sample size .

So, using the shortcut method,


s^2=(10*10,061.91-96,286.09)/(10*9)=48.1446

User Sergi Juanati
by
7.3k points