Question

What are the solutions of 3 x^2-x+4=0

Answer 1

The solution of given equation for x is (0.16 + i 1.14) , (0.16 - i 1.14)

Explanation:

Given as :

The quadratic equation is as 3 x² - x + 4 = 0

Since The given equation is quadratic

∵, Standard quadratic equation is ax² + bx + c = 0

Now, x =
`\frac{-b\pm \sqrt{b^(2) - 4* a* c}}{2* a}`

Comparing the equation

i.e x =
`\frac{-(-1)\pm \sqrt{(-1)^(2) - 4* 3* 4}}{2* 3}`

or, x =
`(1\pm √((1-48)))/(6)`

Or, x =
`(1\pm √((-47)))/(6)`

Or, x =
`(1\pm i6.85)/(6)`

Or, x = (0.16 + i 1.14) , (0.16 - i 1.14)

So, The solution of given equation for x = (0.16 + i 1.14) , (0.16 - i 1.14)

Hence, The solution of given equation for x is (0.16 + i 1.14) , (0.16 - i 1.14) . Answer