Answer:
![x=3.1950](https://img.qammunity.org/2021/formulas/mathematics/middle-school/z26neybqsodgoun6cnaefi3oawaak3xnbt.png)
Explanation:
Given:
The equation to solve is given as:
![\log_8 12=x-2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4kxj3k1q2646ld88ull2oreqs3bgvhp62j.png)
In order to solve this, we use the base change formula of logarithms.
The base change formula is given as:
![\log_a b=(\log b)/(\log a)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bpjtze05tmt7f4s4qdnh8hph07gxq1sc2b.png)
Therefore, the equation can be rewritten as:
![(\log 12)/(\log 8)=x-2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ol1i700u69dvswlt52maqhw2im83gonifq.png)
Adding 2 on both the sides, we get:
![x=2+(\log 12)/(\log 8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/64l2hbwjvstz2z0gfgbj0qcddkaatylug0.png)
Now, we know that,
![\log 12=1.07918\ and\ \log 8=0.9031](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zd3evbynyc1x3f0gjjztocogrz0k1cmaop.png)
Plug in these values and solve for 'x'. This gives,
![x=2+(1.07918)/(0.9031)\\\\x=2+1.19497=3.19497\approx3.1950](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6da55yl3j4nhlv01crqx10kisrdcakg2lf.png)
Therefore, the value of 'x' is 3.1950 rounded to four decimal places.