Question

How do i find the mid point in A(-3,13) B(15,7) and C(-3,11)​

Answer 1

Midpoint of AB=(6,10) ,Midpoint of BC=(6,9) and Midpoint of CA=(-3,12)

Explanation:

Given that the points are A(-3,13), B(15,7) and C(-3,11)​

To find the mid points :

To find midpoint of AB

Let
`(x_1,y_1) and (x_2,y_2)` be the points A(-3,13),B(15,7) respectively

Midpoint of AB
`=((x_1+x_2)/(2),(y_1+y_2)/(2))`

`=((-3+15)/(2),(13+7)/(2))`

`=((12)/(2),(20)/(2))`

`=(6,10)`

Midpoint of AB=(6,10)

To find midpoint of BC

Let
`(x_1,y_1) and (x_2,y_2)` be the points B(15,7),C(-3,11) respectively

Midpoint of BC
`=((x_1+x_2)/(2),(y_1+y_2)/(2))`

`=((15-3)/(2),(7+11)/(2))`

`=((12)/(2),(18)/(2))`

`=(6,9)`

Midpoint of BC=(6,9)

To find midpoint of CA

Let
`(x_1,y_1) and (x_2,y_2)` be the points C(-3,11),A(-3,13),respectively

Midpoint of CA
`=((x_1+x_2)/(2),(y_1+y_2)/(2))`

`=((-3-3)/(2),(11+13)/(2))`

`=((-6)/(2),(24)/(2))`

`=(-3,12)`

Midpoint of CA=(-3,12)

Therefore Midpoint of AB=(6,10) ,Midpoint of BC=(6,9) and Midpoint of CA=(-3,12)