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How do i find the mid point in A(-3,13) B(15,7) and C(-3,11)​

User JakeSays
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1 Answer

4 votes

Answer:

Midpoint of AB=(6,10) ,Midpoint of BC=(6,9) and Midpoint of CA=(-3,12)

Explanation:

Given that the points are A(-3,13), B(15,7) and C(-3,11)​

To find the mid points :

To find midpoint of AB

Let
(x_1,y_1) and (x_2,y_2) be the points A(-3,13),B(15,7) respectively

Midpoint of AB
=((x_1+x_2)/(2),(y_1+y_2)/(2))


=((-3+15)/(2),(13+7)/(2))


=((12)/(2),(20)/(2))


=(6,10)

Midpoint of AB=(6,10)

To find midpoint of BC

Let
(x_1,y_1) and (x_2,y_2) be the points B(15,7),C(-3,11) respectively

Midpoint of BC
=((x_1+x_2)/(2),(y_1+y_2)/(2))


=((15-3)/(2),(7+11)/(2))


=((12)/(2),(18)/(2))


=(6,9)

Midpoint of BC=(6,9)

To find midpoint of CA

Let
(x_1,y_1) and (x_2,y_2) be the points C(-3,11),A(-3,13),respectively

Midpoint of CA
=((x_1+x_2)/(2),(y_1+y_2)/(2))


=((-3-3)/(2),(11+13)/(2))


=((-6)/(2),(24)/(2))


=(-3,12)

Midpoint of CA=(-3,12)

Therefore Midpoint of AB=(6,10) ,Midpoint of BC=(6,9) and Midpoint of CA=(-3,12)

User Camwhite
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