Answer:
spring constant of the spring will be equal to 317.33 N/m
Step-by-step explanation:
We have given mass of the child m = 6.80 kg
Spring is stretched by length of 0.210 m . so x = 0.210 m
Acceleration due to gravity

Force on the child will be equal to

This force will be balanced by spring force
And spring force is equal to F = Kx
So kx = mg

k = 317.33 N /m
So spring constant of the spring will be equal to 317.33 N/m