Answer:
The cross sectional area in mm2 is 7.07

The cross sectional area in cm2 is 0.0707

Step-by-step explanation:
The cross-sectional area (a) of the wire is given by;
a =
x

where d is the diameter of the cross section = 3.00mm
1 => To find the cross-sectional area in
, substitute the value of d = 3.00mm into the equation above as follows;
a =
x

Taking
to be
we have;
a =
x

a = 7.07

2 => To find the cross-sectional area in
, first convert the diameter in mm to cm as follows;
3.00mm = 0.3cm
Now, substitute the value of d = 0.3cm into the equation above as follows;
a =
x

Taking
to be
we have;
a =
x

a = 0.0707
