Question

A package of aluminum foil is 59.3 yd long, 13 in. wide, and 0.00040 in. thick. If aluminum has a density of 2.70 g/cm3, what is the mass, in grams, of the foil?

Answer 1

493.02 g.

Step-by-step explanation:

Density = mass/volume

mass = density×volume

m = D×V ............................ Equation 1

m = mass of the aluminum foil, D = Density of the aluminum foil, V = volume of the aluminum foil.

V = L×W×H................... Equation 2

Where L = length of the aluminum foil, W = wide of the aluminum foil, H = thickness of the aluminum foil.

Given: L = 59.3 yd = 59.3×0.9144 m = 54.224 m, W = 13 in = 13×0.0254 m = 0.3302 m, H = 0.00040 in = 0.00040×0.0254 m = 0.0000102 m.

Substituting into equation 2

V = 54.224×0.3302×0.0000102

V = 0.0001826 m³ = (0.0001826×1000000) cm³

V = 182.6 cm³

Also given D = 2.70 g/cm³

Substitute into equation 1

m = 2.7×182.6

m = 493.02 g.

The mass in grams of the foil = 493.02 g.