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A mechanical system is governed by the following differential equation what is the homogeneous solution

d^2y/dt^2 + 6 dy/dt + 9y = 4e^- t

User Tomoya
by
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1 Answer

3 votes

The ODE has characteristic equation


r^2+6r+9=(r+3)^2=0

with roots
r=-3, and hence the characteristic solution


y_c=C_1e^(-3t)+C_2te^(-3t)

For the particular solution, assume an ansatz of
y_p=ae^(-t), with derivatives


(\mathrm dy_p)/(\mathrm dt)=-ae^(-t)


(\mathrm d^2y_p)/(\mathrm dt^2)=ae^(-t)

Substituting these into the ODE gives


ae^(-t)-6ae^(-t)+9ae^(-t)=4ae^(-t)=4e^(-t)\implies a=1

so that the particular solution is


\boxed{y(t)=C_1e^(-3t)+C_2te^(-3t)+e^(-t)}

User Kkuilla
by
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