123k views
4 votes
Determine the range of the function f(x)=x^2-2/2 when the domain is {0, 2}.
HELP

User MFlamer
by
8.9k points

1 Answer

4 votes

The range of function is { -1, 1 }

Solution:

Given that, the function is:


f(x) = (x^2-2)/(2)

Domain is {0, 2 }

We have to find the range of function

The domain refers to the set of possible input values

The range is the set of possible output values

Here domain is x = 0 and x = 2

Substitute x = 0 in given function


f(0) = (0-2)/(2)\\\\f(0) = (-2)/(2)\\\\f(0) = -1

Substitute x = 2 in given function


f(2) = (2^2-2)/(2)\\\\f(2) = (4-2)/(2)\\\\f(2) = (2)/(2) = 1

Thus the range of function is { -1, 1 }

User Dan Parker
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories