Question

An experiment was performed on a 2-kg block. Forces of 5, 10, and 15 newtons respectively were applied to the block for 5 seconds. Describe the difference in acceleration between the three trials.

Answer 1

With the increase of force by 5 N, the acceleration is increasing by 2.5 m/s².

Step-by-step explanation:

Given:

Forces acting are 5 N, 10 N and 15 N

Mass of the block is (m) = 2 kg

From Newton's second law, we know that acceleration acting on an object is directly proportional to the force acting on it and inversely proportional to its mass.

Therefore, the acceleration of the block is given as:

`a=(Force)/(mass)\\\\a=(F)/(m)`

Now, the mass is constant. So, the acceleration only depends on the force applied.

When the force is 5 N, the acceleration is given as:

`a_1=(5\ N)/(2\ kg)=2.5\ m/s^2`

When the force is 10 N, the acceleration is given as:

`a_2=(10\ N)/(2\ kg)=5\ m/s^2`

When the force is 15 N, the acceleration is given as:

`a_3=(15\ N)/(2\ kg)=7.5\ m/s^2`

So, difference between
`a_1\ and\ a_2` is given as:

`a_2-a_1=5-2.5=2.5\ m/s^2`

difference between
`a_2\ and\ a_3` is given as:

`a_2-a_1=7.5-5=2.5\ m/s^2`

Therefore, with the increase of force by 5 N, the acceleration is increasing by 2.5 m/s².