Answer:
Therefore,
![\tan S=2.14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/sxs6v397tqdg05u3kpwft0gu6lmjmnb51m.png)
Explanation:
Given:
ΔSRQ is a Right angle triangle at ∠R = 90°
SR = 36 ....Adjacent side of ∠S
RQ = 77 ...Opposite side of ∠S
To Find:
![\tan S=?](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8bgqmilh8fyp0zgu9zbvjjy4y4euxehg93.png)
Solution:
ΔSRQ is a Right angle triangle at ∠R = 90° ..Given
By Tangent Identity we have
![\tan S = \frac{\textrm{side opposite to angle S}}{\textrm{side adjacent to angle S}}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nf1be06cekg50qfftqwzyzekbl1g2brxpy.png)
Substituting the values we get
...Rounded to the nearest hundredth
Therefore,
![\tan S=2.14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/sxs6v397tqdg05u3kpwft0gu6lmjmnb51m.png)