112k views
3 votes
What is the equation of the line that is parallel to y = –4x + 3 and has a y-intercept of -1/3

1 Answer

5 votes

The equation of the line that is parallel to given line is 12x + 3y = -1

Solution:

Given that, the line that is parallel to y = –4x + 3 and has a y-intercept of -1/3

Given equation of line is:

y = -4x + 3

Let us first find the slope of line

The equation of line in slope intercept form is given as:

y = mx + c ------- eqn 1

Where, "m" is the slope and "c" is the y intercept

On comparing the above slope intercept form with given equation of line, we get m = -4

Thus the slope of line with equation y = -4x + 3 is -4

We have to find the slope of line that is parallel to above line

We know that slopes of parallel lines are equal

Therefore, slope of line passing parallel to given line is -4

Now find the equation of line


\text{Substitute } m = -4 \text{ and } c = (-1)/(3) \text{ in eqn 1 }


y = -4x -(1)/(3)\\\\3y = -12x -1\\\\12x + 3y = -1

Thus the equation of line is found

User LogicStuff
by
6.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.