Good morning ☕️
Answer:
an= 4 . (2)ⁿ⁻¹
an= 3 + 4(n-1)
an = 4+2(n-1)
an = 2 + 3(n-1)
an = 3 . (4)ⁿ⁻¹
a, = 2 · (3)9 - 1
→ an arithmetic sequence with a first term of 2 and a common difference of 3
an = 2 + 3(n-1)
→ a geometric sequence with first term of 4 and a common ratio of 2
an= 4 . (2)ⁿ⁻¹
→ a geometric sequence with first term of 3 and a common ratio of 4
an = 3 . (4)ⁿ⁻¹
→ an arithmetic sequence with a first term of 3 and a common difference of 4
an= 3 + 4(n-1)
:)