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F(x) = x − 8, g(x) = x2 Find (f + g)(x)

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(f+g)(x) \text{ is equal to } x^2+x-8

Solution:

Given that the functions are:


f(x) = x-8\\\\g(x)=x^2

We have to find the value of (f + g)(x)

By operations on functions, we know that,

(f + g)(x) = f (x) + g(x)

Thus (f + g)(x) can be found by adding both the given functions


(f + g)(x) = f (x) + g(x)\\\\(f + g)(x) = x - 8 + x^2\\\\(f + g)(x) = x^2+x-8

Thus (f + g)(x) is equal to
x^2+x-8

User Andrey Frolov
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