Question

A baseball player throws a ball from second base to home plate. How far does the player throw the ball?

Round your number to the nearnest tenth.
Answer: _______ ft​

Answer 1

The player throws 127.3 ft from second base to home plate.

Explanation:

Given:

Distance from home to first base = 90 ft

Distance from first base to second base = 90 ft

We need to find the distance from second base to home.

Solution:

Now we can assume the complete scenario to be formed as a right angled triangle with two sides given and to find the third side.

Now by using Pythagoras theorem which states that;

Square of the hypotenuse side is equal to sum of squares of other two sides.

framing in equation form we get;

distance from second base to home =
`√(90^2+90^2)= 127.27 \ ft`

Rounding to nearest tent we get;

distance from second base to home = 127.3 ft

Hence The player throws 127.3 ft from second base to home plate.