Question

Does anybody know how to determine the angle again? of Q.B

Answer 1

Therefore the measur angle ACB

`m\angle ACB=61.93\°`

Explanation:

Given:

ΔABC is a right Triangle at ∠A = 90°

AB = 15 ....Side Opposite to ∠ACB

AC = 8 ....Side Adjacent to ∠ACB

To Find:

m∠ACB = ?

Solution:

In Right Angle Triangle ABC, Tangent Identity we have

`\tan (\angle ACB) = \frac{\textrm{side opposite to angle ACB}}{\textrm{side adjacent to angle ACB}}`

Substituting the values we get

`\tan (\angle ACB) = (AB)/(AC)=(15)/(8)=1.875\\\\\angle ACB=\tan^(-1)(1.875)\\m\angle ACB=61.93\°`

Therefore the measur angle ACB

`m\angle ACB=61.93\°`